3x^2=-8x+5

Solution for 3x^2=-8x+5 equation:

3x^2=-8x+5

We move all terms to the left:

3x^2-(-8x+5)=0

We get rid of parentheses

3x^2+8x-5=0

a = 3; b = 8; c = -5;
Δ = b2-4ac
Δ = 82-4·3·(-5)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{31}}{2*3}=\frac{-8-2\sqrt{31}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{31}}{2*3}=\frac{-8+2\sqrt{31}}{6}
$